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x^2-x=812
We move all terms to the left:
x^2-x-(812)=0
We add all the numbers together, and all the variables
x^2-1x-812=0
a = 1; b = -1; c = -812;
Δ = b2-4ac
Δ = -12-4·1·(-812)
Δ = 3249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3249}=57$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-57}{2*1}=\frac{-56}{2} =-28 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+57}{2*1}=\frac{58}{2} =29 $
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